Circle (A16): The midpoint reflection of Bankoff's triplet circle
Reflect (A2) through the midpoint M' of the midpoints M1 and M2 of the arcs (O1) and
(O2), and the result is the Archimedean circle (A16) [Dodge e.a. 1999].
- (A16) is tangent to the arc (O) at its midpoint M. The circle on diameter M1M2 passes
through this point M as well.
- The center A16 lies on OM.
- Let T be the point on CD beyond D such that AB=CT. The center A16
is the Circumenter of triangle ABT [Bui 2007]
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