Circles (A54a) and (A54b): The O-basal pair


Let the perpendicular to AB at O, on which we find A27, meet the semicircle (O1O2)=(O') at E. The perpendiculars to BE and AE meet AB at A54a and A54b. The circles with these points as centers and passing through O are Archimedean. [FvL, 20 Mar 2008]

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